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Q.

A body starts from rest and travels with a uniform acceleration of 5 m/s2and then decelerates at a uniform rate of 3 m/s2 again to come to rest. Total time of travel is 10s . Then the maximum velocity attained by the body is

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answer is 18.75 .

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Detailed Solution

Acceleration  a1=5 m/s2Deceleration  a2=3 m/s2Total time  T=10 S.∴The maximum velocity attained                                 Vmax=a1a2a1+a2T=5×38×10=1508=18.75m/s
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