A body starts with an initial velocity of 10 ms-1 and is moving along a straight line with constant acceleration. When the velocity of the particle is 50 ms-1, the acceleration is reversed in direction. The velocity of the particle when it again reaches the starting point is

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70 ms-1

60 ms-1

10 ms-1

30 ms-1

answer is A.

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Detailed Solution

(50)2=(10)2+2as….(i)v2=(50)2+2(-a)(-s)=(50)2+2as….(ii)Solving these two equations, we get v=70 m/s

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