A body is thrown at an angle 300 to the horizontal with the velocity of 30 m/s. After 1 sec, its velocity will be (in m/s) (g = 10 m/s2)

Horizontal component of velocityvx =ux =u cos θ=30 × cos 300=153m/s                             Vertical component of the  velocityvy = u sinθ– gt = 30                             vy =30sin 300–10  ×1=5 m/s                             v2 = vx2 + vy2 = 700                              ⇒  v = 107m/s                             Hence correct answer is (I)