First slide

Projection Under uniform Acceleration

Question

A body thrown horizontally from the top of tower strikes the ground after three seconds at an angle 45° with the horizontal. The speed with which the body was projected

Easy

A

9.8 ms^–1
B

19.6 ms^–1
C

29.4 ms^–1
D

32.4 ms^–1

Solution

$\begin{array}{l} ∵ \tan θ = \frac{V_{y}}{V_{x}} \Rightarrow 1 = \frac{V_{y}}{V_{x}} \\ ∵ θ = 45^{\circ} \Rightarrow u = gt = 9 .8 \times 3 \\ = 29 .4 {ms}^{- 1} \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App