First slide

Projection Under uniform Acceleration

Question

A body is thrown horizontally with a velocity of v m/s from the top of a tower of height 2h reaches the ground in ‘t’ seconds. If another body double the mass is thrown horizontally with a velocity 5v from the top of another tower of height 8h it reaches the ground in a time of

Moderate

A

2 t
B

4 t
C

6 t
D

8 t

Solution

time of flight for horizontal projection.
$t = \sqrt{\frac{2 h}{g}}; \frac{t_{1}}{t_{2}} = \sqrt{\frac{h_{1}}{h_{2}}} = \sqrt{4} = 2$

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