First slide

Vertical projection from ground

Question

A body thrown up vertically has a speed of 32 m/s, when it reaches half of the maximum height. It rises through a further height of ( g = 10 m/s²) :

Easy

A

102.4 m.
B

64 m.
C

51.2 m.
D

$32 \sqrt{2} m$

Solution

Height from there $h = \frac{U^{2}}{2 g} = \frac{32 \times 32}{20} = 51 .2 m$

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