A body is thrown up with a velocity 100 m s-1. It travels 5 m in the last second of its journey. If the same body is thrown up with a velocity 200 ms-1, how much distance (in metre) will it travel in the last second (g = 10 m s-2)?

s=u+a2(2n−1)u=100ms−1,a=−10ms−2 and s=5m5=100−5(2n−1) gives n=10sBody when thrown up with velocity 200 ms-1 will take 20 s to reach the highest point. Distance travelled in 20th second is 200−5(200×2−1)=5mIn the last second of upward journey, the bodies will travel same distance.