First slide

Vertical projection from ground

Question

A body is thrown up with a velocity ‘u’. It reaches maximum height ‘h’. If its velocity of projection is doubled the maximum height it reaches is ___

Moderate

A

4h
B

h
C

2h
D

3h

Solution

$\large h \propto {u^2}$
$\large \frac{h}{{{h_2}}} = {\left( {\frac{{{u_1}}}{{{u_2}}}} \right)^2} \Rightarrow \frac{h}{{{h_2}}} = {\left( {\frac{u}{{2u}}} \right)^2} \Rightarrow {h_2} = 4h$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App