A body is thrown vertically up with certain initial velocity, the potential and kinetic energies of the body are equal at a point P in its path. If the same body is thrown with double the velocity upwards, the ratio of potential and kinetic energies of the body when it crosses the same point, is
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a
1 : 1
b
1 : 4
c
1 : 7
d
1 : 8
answer is C.
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Detailed Solution
In first case, at ‘P’ ,TE=PE+KE=2PEand TEbottom=12mu2In second case,TE1bottom=12m2u2=4TE=8PE At 'P', PE1KE1=PE1TE1-PE1=PE8TE-PE