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Q.

A body is thrown vertically up with a velocity u. It passes three points A, Band e in its upward journey with velocities u2,u3 and u4, respectively. The ratio of the separations between points A and B and between B and C, i.e. ABBC is

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a

1

b

2

c

107

d

207

answer is D.

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Detailed Solution

A⇒u24-u2=-2gh1B⇒u29-u2=-2gh2C⇒u216-u2=-2gh3∴           AB=u22g89-34=u22g·536                       BC=u22g1516-89=u22g·7144∴                   ABBC=536×1447=207
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