A body is thrown vertically upward. At half of the maximum height, the velocity of the body is  10m/s. The maximum height reached by the body is

Let ‘u’ be the initial velocity ∴ At half of the maximum height, let  ‘v’, be the final velocity.∴ From equation  v2−u2=2as⇒v2−u2=−2gh2.........(i) v1=10 m/s We know that maximum height reached by the body is h=u22g⇒u2=2ah∴ From (i) 100−(2gh)=−gh⇒gh=100∴h=100g=10010=10mII method: At highest point v=0v2-u2=2as 02-102=2(-10)h h=5 H2=5 H=10m