First slide

Projection Under uniform Acceleration

Question

A body is thrown with velocity (4i + 3j ) metre per second. Its maximum height is (g = 10 ms^–2)

Moderate

Solution

$\large \overrightarrow u = \left( {4\widehat i + 3\widehat j} \right)m/s$
$\large \therefore$ u sinθ = 3 m/s
$\large {H_{\max }} = \frac{{{u^2}{{\sin }^2}\theta }}{{2g}} = \frac{{{{(3)}^2}}}{{2 \times 10}} = 0.45m$

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