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Q.

A body is thrown with the velocity v0 at an angle of θ to the horizon. Determine v0 in ms-1 if the maximum height attained by the body is 5 m and at the highest point of its trajectory the radius of curvature is r = 3 m. Neglect air resistance. [Use 80 as 9] Take g=10ms-2

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answer is 9.

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Detailed Solution

Radius of curvature at the highest pointr=v2g⇒r=v0cos⁡θ2gv0cos⁡θ=gr               …(i)Maximum height, h=v02sin2⁡θg⇒v0sin⁡θ=gh        …(ii)By using Equations (i) and (ii), we getv02sin2⁡θ+v02cos2⁡θ=gh+gr=g(h+r)v0=g(h+r)⇒ v0=10(5+3)=9ms−1
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