A body is thrown with the velocity vo at an angle of θ to the horizon. Determine vo in ms-1 if the maximum height attained by the body is 5 m and at the highest point of its trajectory the radius of curvature is r = 3 m. Neglect air resistance. [Use 80 = 9 and g =10 m/s2]
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answer is 9.
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Detailed Solution
Radius of curvature at the highest pointmv2r=mg r=v2g⇒r=v0cosθ2gv0cosθ=gr ……… (i)Maximum height, h=v02sin2θg⇒v0sinθ=gh ………. (ii)By using Eqs (i) and (ii), we getv02sin2θ+v02cos2θ=gh+gr=g(h+r)⇒ v0=g(h+r)=10(5+3)=9ms−1