First slide
Rectilinear Motion
Question

A body travels 200 cm in the first 2 s and 220 cm in the next 4 s with deceleration. The velocity of the body at the end of the seventh second is

Moderate
Solution

200=u×2(1/2)a(2)2 or  ua=100                                          ....(i) 200+220=u(2+4)(1/2)(2+4)2a or  u3a=70                                          ....(ii)

 Solving Eqs (i) and (ii), we get a=15cms2 and u=115cms1

 Further, v=uat=11515×7=10cms1

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