A body travels for 15sec starting from rest with a constant acceleration .  If it travels distances x, y and z in the first 5 sec,second 5 sec and the next 5 sec respectively.   The relation between x, y and z is

:given initial velocity u=0; A to B→ time t= 5sec;displacement s=x ;substitute in S=ut +   12 a  t2 x  =    12 a  (5)2 --           →    (1)A to C→given S=x+y; u=0;t=5+5;substitute in S=ut +   12 a  t2 x+y  =    12 a  (5+5)2 --         →    (2)A to D→S=x+y+z; u=0;t=5+5+5sec;substitute in S=ut +   12 a  t2 x+y+z  =    12 a  (5+5+5)2 --         →    (3) divide equation(2) by equation(1)Dividing equation (2) by equation (1), we get,x+yx  =   4⇒   y   =    3x x =y3---(4) divide equation(3) by equation (2)x+y+zx+y   =    94 substitute y=3x in above equation4x+z4x   =    94 ⇒z=5x ⇒x=z5---(5)equate equations (4) and (5) x  =   y3   =   z5