A body travels uniformly a distance of (13.8±0.2) m in a time (4.0±0.3) s. Its velocity with error limits is
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a
(3.5±0.6)ms-1
b
(3.5±0.3)ms-1
c
(6.1±0.6)ms-1
d
(6.1± 0.3) ms-1
answer is B.
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Detailed Solution
Here s = (13.8 ± 0.2)mT = (4.0±0.3)s∴ Velocity v = st = 13.84.0 = 3.45 ms-1(Rounded off to first place of decimal)∴ ∆vv = ∆ss+∆tt = 0.213.8+0.34.0= 0.8×4.1413.8×4.0 = 4.9413.8×4.0 = 0.0895or ∆v = v×0.0895 = 3.45×0.0895 = 0.3087∴ velocity = (3.5±0.3)ms-1