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Q.

A body travels uniformly a distance of (40.0±0.1) m in time (2.0±0.04)s. The velocity of the body is

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a

(5.0±0.4)ms−1

b

(5.0±0.2)ms−1

c

(20±0.6)ms−1

d

(20±0.45)ms−1

answer is D.

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Detailed Solution

V=St=402=20  ΔVv=ΔSs+Δtt⇒ΔV=V[ΔSs+Δtt]                                         =20[0.140+0.042]                                          =0.45                        ⇒V±ΔV=20±0.45
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