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Q.

A body is vibrating in simple harmonic motion. If its acceleration is 12 cms-2 at a displacement 3 cm from the mean position, then time period is

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a

6.28 s

b

3.14 s

c

1.57 s

d

2.57 s

answer is B.

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Detailed Solution

a  = ω2x                       12 = ω2(3)∴                   ω = 2 rad s-1=2πTor                    T = (π) s  or 3.14 s
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