Q.
A body of volume V and density ρ is initially submerged in a liquid of densityσ . If it is lifted through a height h in the liquid, its potential energy will
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a
Increase by hV(ρ−σ)g
b
Decrease by hV(ρ−σ)g
c
Increase by hVρgσ
d
Decrease by hVρgσ
answer is A.
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Detailed Solution
Resultant downward force on the body is F=Vρg−Vσg=V(ρ−σ)g When it is lifted up thenWork done = Force × Distance ⇒ W=V(ρ−σ)gh So, potential energy increases by hV(ρ−σ)g