First slide
Fluid statics
Question

A body of volume v and density p is initially suberged in a liquid of density o. It is lifted through a height h in the liquid. Its potential energy

Easy
Solution

 Resultant downward force on the body is
F=vρgvσg=v(ρσ)g When it is liffed uP, then workdoae =Force x distance or W=V(ρσ)g×h Therefore, potential energy increases by hv(ρσ)g

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