First slide

Variation of g

Question

A body weighs 72 N on the surface of the earth. What is the gravitational force on it, at a height equal to half the radius of the earth ?

Easy

A

32 N
B

30 N
C

24 N
D

48 N

Solution

$\begin{array}{l} mg = 72 \\ \frac{g^{1}}{g} = {(\frac{R}{R + h})}^{2} \\ \frac{g^{1}}{g} = {(\frac{2 R}{3 R})}^{2} \end{array}$
$\begin{array}{l} g^{1} = \frac{4}{9} g \\ F^{1} = m g^{1} \\ = m x \frac{4}{9} g \\ = \frac{4}{9} \times 72 = 32 N \end{array}$

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