First slide

Variation of g

Question

A body of weight 72N moves from the surface of earth at a height half of the radius of the earth, then gravitational force exerted on it will be :

Easy

A

36 N
B

144 N
C

32 N
D

50 N

Solution

F =mg= 72N,
$\begin{array}{l} F' = mg = mg {(\frac{R_{e}}{R_{e} + h})}^{2} \\ = mg \times \frac{4}{9} = 32 N \end{array}$

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