First slide

Friction on horizontal surface

Question

A body of weight 50 N placed on a horizontal surface is just moved by a force of 282 N. The frictional force and normal reaction are

Moderate

A

2 N, 3N
B

5 N, 6 N
C

10 N, 15 N
D

20N, 30N

Solution

Frictional force, $f = 28.2 \cos 45 °$
$= 28.2 \times \frac{1}{\sqrt{2}} = 20 N$
Normal reaction, $R = 50 - 28.2 \sin 45 °$
$= 50 - 20 = 30 N$

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