First slide

Kinetic friction

Question

A body of weight 64 N is pushed with just enough force to start and move it across a horizontal floor and the same force continues to act afterwards. If the coefficients of static and dynamic friction are 0.6 and 0.4 respectively, the acceleration of the body will be (Acceleration due to gravity = g)

Moderate

A

$\frac{g}{6 .4}$
B

0.64 g
C

$\frac{g}{32}$
D

0.2 g

Solution

Weight of the body = 64 N
so mass of the body $m = 6 .4 kg, μ_{s} = 0 .6, μ_{k} = 0 .4$
$\begin{aligned} Net acceleration = \frac{Appliedforce - Kinetic friction}{Mass of the body} \\ = \frac{μ_{s} mg - μ_{k} mg}{m} = (μ_{0} - μ_{k}) g = (0 .6 - 0 .4) g = 0 .2 g . \end{aligned}$

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