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A body with mass 5 kg is acted upon by a force F=(3i^+4j^)N.If its initial velocity at t = 0 is v=(6i^12j^)ms1,then the time at which it will just have a velocity along x-axis is

a
12 s
b
14 s
c
10 s
d
15 s

detailed solution

Correct option is D

a→=Fm=−35i^+45j^m/s2Velocity is along x-axis when y-component of velocity becomes zero.vy=uy+ayt 0 = (–12) + (4/5) t 12 = 4/5 t ∴t=12×54=15 s

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