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Q.

A body with mass 5 kg is acted upon by a force F→=(−3i^+4j^)N.If its initial velocity at t = 0 is v→=(6i^−12j^)ms−1,then the time at which it will just have a velocity along x-axis is

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a

12 s

b

14 s

c

10 s

d

15 s

answer is D.

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Detailed Solution

a→=Fm=−35i^+45j^m/s2Velocity is along x-axis when y-component of velocity becomes zero.vy=uy+ayt 0 = (–12) + (4/5) t 12 = 4/5 t ∴t=12×54=15 s
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