Q.

A body 'x' with a momentum 'p' collides with another identical stationary body 'y' one dimensionally. During the collision 'y' gives an impulse 'J' to the body 'x'. Then the coefficient of restitution is

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a

2Jp−1

b

Jp+1

c

Jp−1

d

J2p−1

answer is A.

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Detailed Solution

Initial momentum of body - 1 = P. As the impulse transferred by y to x is in a direction opposite to the direction of initial motion of x, its final momentum mv2 =p+(−J)Also, since impulse transferred by x to y is in the direction of motion of y , we can write, mv2=J∴e=v2−v1u1−u2=mv2−mv1mu1=J−(p−J)p ∴e=2Jp−1
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A body 'x' with a momentum 'p' collides with another identical stationary body 'y' one dimensionally. During the collision 'y' gives an impulse 'J' to the body 'x'. Then the coefficient of restitution is