Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A bodyweighs 72 Non the surface of the earth. What is the gravitational force on it due to earth at a height  equal to half the radius of the earth from the surface ?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

16 N

b

28 N

c

32 N

d

72 N

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Let W1 be the weight of the body on the surface of the earth. If W2 be the gravitational force on the body due to earth at height R2 above the surface of the earth, thenW1W2=g1g2=R22R12where R1 =radius of the earth.Here R1 = R  and R2 =R+R2∴ W1W2=R+R2R2=94Or W2=W1×49=72×49=32N
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring