A bomb is dropped from an aeroplane when it is at a height h directly above a target. If the aeroplane is moving horizontally at a speed v, the distance bywhich the bomb will miss the target is given by
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a
2v(h/g)
b
V(h/g)
c
V(2h/g)
d
V(h/2g)
answer is C.
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Detailed Solution
The time taken by the bomb to hit the ground is given byh=0×t+12gt2 or (2h/g)=t2∴ t=(2h/g)Horizontal speed of aeroplane = Horizontal speed of bomb (= v)The distance by which the bomb will miss the target is given by= horizontal velocity , time=vt=v(2h/g)