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Q.

A bomb falling freely bursts after 10 sec. (g=10ms−2) into two fragments of masses in the ratio of  2 : 1. The velocity of heavier fragment immediately after the explosion is 200ms−1 vertically downwards. The velocity of the lighter fragment immediately after the explosion is

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a

50ms−1  upward

b

75ms−1  downward

c

100ms−1  upward

d

400ms−1  upward

answer is C.

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Detailed Solution

t=10s,  V=gt=10×10=100ms−1 V¯=−100j,  P¯i=−m×100j P¯f=−23m×200j+m3V2¯ −100mj=−4003mj+m3V2¯ V2¯=−300j+400j=100j i.e 100ms−1  upwards.
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