Question

A bomb falling freely bursts after 10 sec. (g=10ms^-2) into two fragments of masses in the ratio of 2:1. The velocity of heavier fragment immediately after the explosion is 200 ms^-1 vertically downwards. The velocity of the lighter fragment immediately after the explosion is

Moderate

Solution

u=gt =10 $\times$ 10 m/s = 100 m/s ( downward)
Conserving momentum , mv + 2m $\times 200 = 3 m \times 100$
$\Rightarrow v = - 100 m / s$ (upward )

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