A bomb is kept stationary at a point. It suddenly explodes into two fragments of masses $$1$$ g and $$3$$ g. The total K.E. of the fragments is $$6.4$$×$$104J$$. What is the K.E. of the smaller fragment

Question

A bomb is kept stationary at a point. It suddenly explodes into two fragments of masses $$1$$ g  and $$3$$ g. The total K.E. of the fragments is $$6.4$$×$$104J$$. What is the K.E. of the smaller fragment

Infinity Learn · Accepted Answer

As the momentum of both fragments are equal therefore $$E1E2=m2m1=31$$ i.e. $$E1=3E2$$       …(i)According$$ to problem  $$E1+E2=6.4$$×$$104J$$                                                                          …$$(ii) By solving equation (i) and (ii) we get $$E1=4.8$$×$$104J$$  and  $$E2=1.6$$×$$104J$$

A bomb is kept stationary at a point. It suddenly explodes into two fragments of masses 1 g and 3 g. The total K.E. of the fragments is $6 .4 \times 10^{4} J$ . What is the K.E. of the smaller fragment

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A bomb is kept stationary at a point. It suddenly explodes into two fragments of masses 1 g and 3 g. The total K.E. of the fragments is 6.4×104J. What is the K.E. of the smaller fragment

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A bomb is kept stationary at a point. It suddenly explodes into two fragments of masses 1 g and 3 g. The total K.E. of the fragments is $6 .4 \times 10^{4} J$ . What is the K.E. of the smaller fragment