A bomb is kept stationary at a point. It suddenly explodes into two fragments of masses 1 g and 3 g. The total K.E. of the fragments is 6.4×104J. What is the K.E. of the smaller fragment
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a
2.5×104J
b
3.5×104J
c
4.8×104J
d
5.2×104J
answer is C.
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Detailed Solution
As the momentum of both fragments are equal therefore E1E2=m2m1=31 i.e. E1=3E2 …(i)According to problem E1+E2=6.4×104J …(ii) By solving equation (i) and (ii) we get E1=4.8×104J and E2=1.6×104J