A bomb of 12 kg divides in two parts whose ratio of masses is 1 : 3. If kinetic energy of smaller part is 216 J, then momentum of bigger part in kg-m/sec will be

The bomb of mass 12kg divides into two masses m1 and m2 then m1+m2=12      …(i)and  m1m2=13                              …(ii)by solving we get m1=3kg and  m2=9kgKinetic energy of smaller part =  12m1v12=216J∴v12=216×23⇒v1=12m​/​sSo its momentum =  m1v1=3×12=36 kg​-​m​​​/​sAs both parts possess same momentum therefore momentum of each part is  36 kg​-​m​​​/​s