Q.
A bomb of 12 kg divides in two parts whose ratio of masses is 1 : 3. If kinetic energy of smaller part is 216 J, then momentum of bigger part in kg-m/sec will be
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answer is 36.
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Detailed Solution
The bomb of mass 12kg divides into two masses m1 and m2 then m1+m2=12 …(i)and m1m2=13 …(ii)by solving we get m1=3kg and m2=9kgKinetic energy of smaller part = 12m1v12=216J∴v12=216×23⇒v1=12m/sSo its momentum = m1v1=3×12=36 kg-m/sAs both parts possess same momentum therefore momentum of each part is 36 kg-m/s
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