A bomb of 12 kg explodes into two pieces of masses 4 kg  and 8 kg. The velocity of 8kg mass is 6 m/sec. The kinetic energy of the other mass is

As the initial momentum of bomb was zero, therefore after explosion two parts should possess numerically equal momentum i.e. mAvA=mBvB  ⇒4×vA=8×6  ⇒vA=12 ​m​/​s∴Kinetic energy of other mass A, =  12mAvA2=12×4×(12)2=288J