Q.

A bomb of mass 3.0 Kg explodes in air into two pieces of masses 2.0 kg and 1.0 kg. The smaller mass goes at a speed of 80 m/s. The total energy imparted to the two fragments is

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a

1.07 kJ

b

2.14 kJ

c

2.4 kJ

d

4.8 kJ

answer is D.

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Detailed Solution

Both fragment will possess the equal linear momentum m1v1=m2v2⇒1×80=2×v2⇒v2=40 m​.​/​s∴ Total energy of system =12m1v12+12m2v22=12×1×(80)2+12×2×(40)2= 4800 J = 4.8 kJ
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