Q.
A bomb of mass 3.0 Kg explodes in air into two pieces of masses 2.0 kg and 1.0 kg. The smaller mass goes at a speed of 80 m/s. The total energy imparted to the two fragments is
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a
1.07 kJ
b
2.14 kJ
c
2.4 kJ
d
4.8 kJ
answer is D.
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Detailed Solution
Both fragment will possess the equal linear momentum m1v1=m2v2⇒1×80=2×v2⇒v2=40 m./s∴ Total energy of system =12m1v12+12m2v22=12×1×(80)2+12×2×(40)2= 4800 J = 4.8 kJ
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