A bomb of mass 9kg explodes into 2 pieces of mass 3kg and 6kg. The velocity of mass 3kg is 1.6 m/s, the K.E. of mass 6kg is

As the bomb initially was at rest therefore Initial momentum of bomb = 0Final momentum of system =  m1v1+m2v2As there is no external force∴m1v1+m2v2=0⇒3×1.6+6×v2=0velocity of 6 kg mass v2=0.8 m​/​s (numerically)Its kinetic energy =12m2v22=12×6×(0.8)2=1.92 J