A bomb of mass 30 kg at rest explodes into two pieces of masses 18 kg and 12 kg. The velocity of 18 kg mass is 6 ms-1 . The kinetic energy of the other mass is
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a
256 J
b
486 J
c
524 J
d
324 J
answer is B.
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Detailed Solution
According to law of conservation of linear momentum mAvA=mBvB=18×6=12×vB⇒vB=9 m/s K.E. of mass 12 kg, EB=12mBvB2=12×12×(9)2=486J