A Bomb of mass 16kg at rest explodes into two pieces of masses 4kg & 12kg.  The velocity of the mass 12kg is 4 m/s.   The K.E. of the other mass is

Linear momentum is conserved. apply principle of conservation of linear momentum ∴     0    =    m1v1+m2v2 here m1=4kg;m2=12kg;v2=4m/s;substitute ⇒ 4×v1+    12×4   =    0 ⇒ v1=-    12m/s       ∴    K.E1   =    12  m1v12 substitute                         K.E1=12  (4)×(−12)2     K.E1=288 joule