A Bomb of mass 16kg at rest explodes into two pieces of masses 4kg & 12kg. The velocity of the mass 12kg is 4 m/s. The K.E. of the other mass is
96 J
144 J
288 J
192 J
Linear momentum is conserved. apply principle of conservation of linear momentum ∴ 0 = m1v1+m2v2 here m1=4kg;m2=12kg;v2=4m/s;substitute ⇒ 4×v1+ 12×4 = 0 ⇒ v1=- 12m/s ∴ K.E1 = 12 m1v12 substitute K.E1=12 (4)×(−12)2 K.E1=288 joule