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A bomb of mass 3m kg explodes into two pieces of mass m kg and 2m kg. If the velocity of m kg mass is 16 m/s, the total kinetic energy released in the explosion is

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a

192 mJ

b

96 mJ

c

384 mJ

d

768 mJ

answer is A.

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Detailed Solution

By the conservation of momentum, mAvA=mBvB⇒m×16=2m×vB⇒vB=8 m/sKinetic energy of system = 12mAvA2+12mBvB2=12×m×(16)2+12×(2m)×82=192m J

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