First slide

Work

Question

A bomb of mass 3m kg explodes into two pieces of mass m kg and 2m kg. If the velocity of m kg mass is 16 m/s, the total kinetic energy released in the explosion is

Moderate

A

192 mJ
B

96 mJ
C

384 mJ
D

768 mJ

Solution

By the conservation of momentum, $m_{A} v_{A} = m_{B} v_{B}$
$\Rightarrow m \times 16 = 2 m \times v_{B} \Rightarrow v_{B} = 8 m / s$
Kinetic energy of system = $\frac{1}{2} m_{A} v_{A}^{2} + \frac{1}{2} m_{B} v_{B}^{2}$
$= \frac{1}{2} \times m \times {(16)}^{2} + \frac{1}{2} \times (2 m) \times 8^{2} = 192$ m J

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