First slide

Motion of centre of mass

Question

A bomb moving in a parabolic path explodes into two fragments of equal masses. The accelaration of the centre of mass of the fragments when both are in air is equal to

Easy

A

g/2
B

2g
C

g
D

zero

Solution

$\large \vec a=\frac {m_1\vec a_1+m_2\vec a_2}{(m_1+m_2)}\\\\=\frac{m\vec g+m\vec g}{m+m}=\vec g$

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