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Q.

A bomb at rest explodes into 3 parts of same mass. The momentum of 2 parts are −2pi^ and pj^.  The momentum of the third part will have a magnitude.

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a

P

b

3P

c

P5

d

Zero

answer is C.

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Detailed Solution

P→i=P→f0=−2Pi^+Pj^+P→P→=−2Pi^+Pj^|P|=4P2+P2=5P
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