A bomber flying with a horizontal velocity of $$500$$ $$km/h$$ at an altitude of $$5$$ km wants to hit a train moving with a constant velocity of $$100$$ $$km/h$$ in the same direction and in the same vertical plane. The angle θ between the line of sight of the target and the horizontal at the instant the bomb should be released is

Question

Infinity Learn · Accepted Answer

Velocity of train relative to bomber is ur, $$thenur=500$$−$$100=400km/h=400$$×(5/18)=(1000/9)m/sThe$$ situation is shown fig. $$(8).Since    $$h=gx22ur2$$∴ $$5000=gx22(1000/9)2=10x22$$×$$(1000/9)2x=3513.65mFurther$$,     $$tan$$⁡θ$$=hxor$$      $$tan$$⁡θ$$=50003513$$⋅$$65=1$$⋅$$423or$$      θ$$=$$$$tan$$−$$1$$⁡$$(1$$⋅$$423)=55$$∘

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material