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Q.

A bomber moving horizontally with 500 m/s drops a bomb which strikes ground in 10 s. The angle of strike with horizontal is

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a

sin-115

b

tan-11

c

tan-115

d

tan-1 5

answer is C.

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Detailed Solution

tan θ = vyvx = gtvx = 10×10500 = 15i.e., θ = tan-115 with horizontal
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