First slide

Projection Under uniform Acceleration

Question

A bomber moving horizontally with 500 m/s drops a bomb which strikes ground in 10 s. The angle of strike with horizontal is

Moderate

A

$\sin^{- 1} \frac{1}{5}$
B

$\tan^{- 1} 1$
C

$\tan^{- 1} \frac{1}{5}$
D

$\tan^{- 1} 5$

Solution

$\tan θ = \frac{v_{y}}{v_{x}} = \frac{gt}{v_{x}} = \frac{10 \times 10}{500} = \frac{1}{5}$
$i . e ., θ = \tan^{- 1} \frac{1}{5} with horizontal$

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