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A bomber moving horizontally with 500 m/s drops a bomb which strikes ground in 10 s. The angle of strike with horizontal is

a
sin-115
b
tan-11
c
tan-115
d
tan-1 5

detailed solution

Correct option is C

tan θ = vyvx = gtvx = 10×10500 = 15i.e., θ = tan-115 with horizontal

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