A bomber plane moves horizontally with a speed of 500 m/s and a bomb released from it, strikes the ground in l0 s. Angle at which it strikes the ground will be (g = l0m/s2)

Horizontal component of velocity vx = 500 m/s and vertical component of velocity while striking the ground.vy = 0 +10×10 = 100 m/s∴ Angle with which it strikes the ground,θ = tan-1(vyvx) = tan-1(100500) = tan-1(15)