First slide

Projection Under uniform Acceleration

Question

A bomber plane moves horizontally with a speed of 500 m/s and a bomb released from it, strikes the ground in l0 s. Angle at which it strikes the ground will be (g = l0 $m / s^{2}$ )

Moderate

A

$\tan^{- 1} (\frac{1}{5})$
B

$\tan^{} (\frac{1}{5})$
C

$\tan^{- 1} (1)$
D

$\tan^{- 1} (5)$

Solution

Horizontal component of velocity $v_{x} = 500 m / s$ and vertical component of velocity while striking the ground.
$v_{y} = 0 + 10 \times 10 = 100 m / s$
$∴$ Angle with which it strikes the ground,
$θ = \tan^{- 1} (\frac{v_{y}}{v_{x}}) = \tan^{- 1} (\frac{100}{500}) = \tan^{- 1} (\frac{1}{5})$

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