The Boolean equation for the circuit given in figure is

• A

  $y=\overline{A}.B+C$

• B

  $y=\overline{A}.(\overline{B}+\overline{C})$

• C

  $y=\overline{A}.(B+\overline{C})$

• D

  $y=\overline{A}.(B+C)$