Both the blocks as shown in the given arrangement are given together a horizontal velocity towardsright. If aCM be the subsequent acceleration of the centre of mass of the system of blocks, then aCMwill be
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a
zero
b
53ms-2
c
73ms-2
d
2 ms-2
answer is D.
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Detailed Solution
aCM= External force Total mass = Force of friction from ground Total mass =0.2×(2+1)(10)1+2=2 ms-2
Both the blocks as shown in the given arrangement are given together a horizontal velocity towardsright. If aCM be the subsequent acceleration of the centre of mass of the system of blocks, then aCMwill be