First slide
Motion of centre of mass
Question

Both the blocks as shown in the given arrangement are given together a horizontal velocity towards
right. If aCM be the subsequent acceleration of the centre of mass of the system of blocks, then aCM
will be

Moderate
Solution

aCM= External force  Total mass = Force of friction from ground  Total mass 

        =0.2×(2+1)(10)1+2=2 ms-2

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