First slide

Work

Question

A box of mass 5kg is kept on a rough horizontal surface. The coefficient of friction between box and surface is 0.5. The work done by kinetic friction in moving the box from A to B and back to A (AB=2m)

Moderate

A

100J
B

0
C

-100J
D

-50J

Solution

$\begin{array}{l} W = W_{AB} + W_{BA} \\ = fscos 180 + fscos 180 \\ = - 2 μ mgs \\ = - 2 \times 0.5 \times 5 \times 10 \times 2 \\ = - 100 J \end{array}$

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