Questions
A box of mass 8 kg is placed on a rough inclined plane of inclination 30°. Its downward motion can be prevented by applying a horizontal force F, then value of F for which friction between the block and the incline surface is minimum, is
detailed solution
Correct option is A
For friction to be minimum,F cosθ = mg sinθ⇒ F = mg tanθ = 8×10×tan300 = 803 NTalk to our academic expert!
Similar Questions
A 30 kg box has to move up an inclined slope of to the horizontal at a uniform velocity of 5 . If the frictional force retarding the motion is 150N, the horizontal force required to move up is (g=10 )
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