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A box of mass 8 Kg is placed on a rough inclined plane of inclination θ . Its downward motion can be prevented by applying an upward pull F parallel to the inclined plane. And it can be made to slide upwards by applying a force 2F parallel to the inclined plane. The coefficient of friction between the box and inclined plane is

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a

b

c

d

answer is A.

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Detailed Solution

F=mgsinθ-fl=mgsinθ-μmgcosθ...............(1)2F=mgsinθ+fl=mgsinθ+μmgcosθ..........(2)2(mgsinθ-μmgcosθ)=mgsinθ+μmgcosθμ=13tanθ

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