A box of mass $$8$$ Kg is placed on a rough inclined plane of inclination θ . Its downward motion can be prevented by applying an upward pull F parallel to the inclined plane. And it can be made to slide upwards by applying a force $$2F$$ parallel to the inclined plane. The coefficient of friction between the box and inclined plane is

Question

A box of mass $$8$$ Kg is placed on a rough inclined plane of inclination θ . Its downward motion can be prevented by applying an upward pull F parallel to the inclined plane. And it can be made to slide upwards by applying a force $$2F$$ parallel to the inclined plane. The coefficient of friction between the box and inclined plane is

Infinity Learn · Accepted Answer

$$F=mgsin$$θ$$-fl=mgsin$$θ$$-$$μmgcosθ...............$$(1)2F=mgsin$$θ$$+fl=mgsin$$θ$$+$$μmgcosθ..........$$(2)2(mgsin$$θ$$-$$μmgcosθ$$)=mgsin$$θ$$+$$μmgcosθμ$$=13tan$$θ

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