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A box of mass 8 kg is placed on a rough inclined plane of inclination θ. Its downward motion can be prevented by applying an upward pull F and it can be made to slide upwards by applying a force 2 F. The coefficient of friction between the box and the inclined plane is

a
(tanθ)/3
b
3tanθ
c
(tanθ)/2
d
2tanθ

detailed solution

Correct option is A

During downward motion:F = mg sinθ− mg cosθDuring upward motion:2F = mg sinθ+μmg cosθSolving above two equations, we get μ =(tanθ)/3

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